The way I would normally do this problem is let u=(cosx), so du=sinxdx Then its just the Integral of u^2? No? With 1/sinx pulled outside of the integral. This is easy to integrate, but apparently is ...
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Solving trigonometric equations
👉 Learn how to solve trigonometric equations. There are various methods that can be used to evaluate trigonometric ...
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Solving a trig function with sine and cosine
👉 Learn how to solve trigonometric equations. There are various methods that can be used to evaluate trigonometric equations ...
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